Question

Write the relation between molar conductivity and molar ionic conductivities for the following electrolytes.
a) KBr
b) Na₂SO4
c) AlCl3​

Answer 1

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The limiting molar conductivities of NaCl, KBr and KCl are 126, 152 and 150 Scm2mol−1 respectively. 

The limiting molar conductivity  Λo for NaBr is calculated by the following expression.

λNaBr∞=λNaCl∞+λKBr∞−λKCl∞

λNaBr∞=126+152−150=128 Scm2mol−1

Answer 2

The relation between molar conductivity and equivalent conductivity is

∧$_{M}$$=n$∧$_{E}$.

Explanation:

Molar conductivity:      

Molar conductivity is the conductance property of a solution containing one mole of the electrolyte or it is a function of the ionic strength of a solution or the concentration of salt. It is therefore not a constant.

For example, Here the given electrolytes and the relation between molar conductivity and molar ionic conductivities,

(a) $KBr$:

If ∧$_{0}$ is molar conductivity of an electrolyte at infinite dilution and λ$^{0} _{+}$ and  λ$^{0} _{-}$ are molar ionic conductivities then,

∧$_{0KBr} =$λ$^{0}_{k^-}+$λ$^{0}_{Br^-}$

(b)$Na$$_{2}$$SO_{4}$:

∧$_{0Na_{2}SO_{4} } =$ $2$λ$^{0}_{Na^{+} }+$ λ$^{0}_{SO^{2+} _{4} }$

(C) $AlCl3$:

∧$_{0AlCl_{3} }$   $=$λ$^0_{Al_{3+} }$ $+3$λ$^{0}_{Cl^{-} }$