Question

Write the relation between universal constant and acceleration due to gravity?​

Answer 1

Answer:

g=R2G this is answer

may be right

Answer 2

$\huge\sf\star$ Concept

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The Falling of body object from a height towards the earth under gravitational force of earth with no other force acting on it and such a body is known as free falling body .

$\sf\implies$ The uniform acceleration produced in a freely falling body due to gravitational force of the earth is known as acceleration due to gravity.

$\sf\huge\implies$ S.I unit :- $ms^{-2}$

$\rightarrow$ g does not depend on the mass of the falling object or smaller mass.

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Calculation :

• Force exerted by the earth on body

• F = G $\frac{Mm}{R²}$

• This force by earth produces acceleration in the stone moves downwards.

• Force = mass × acceleration

• $\color{red} { F\: = \: m \: × \: a}$

• G $\frac{Mm}{R²}$ = m × a

$\sf\huge\implies$small m will be cancel out

• A = G $\frac{M}{R²}$

• g = ( 6.67 × $10^{-11}$ N$m^{-11}$ / kg² × 6 × 10²⁴ Kg ) 6.4 × 10⁶

$\sf\huge\implies$$\color{red} {g\: = \: 9.8\: ms^{-2}}$