Math, asked by ananyaubhat231, 1 month ago

Write the relationship between mean and variance of a Bernoulli distribution

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Answered by priyankakumarikul244
1

Answer:

The difference between variance Bernoulli distribution

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Answered by kumark54321
0

Answer:

The relationship between mean and variance of a Bernoulli distribution

is a binomial variable's variance is always lower than its mean.

Step-by-step explanation:

Bernoulli distribution :

The outcome of the Bernoulli random variable may only be either   or  , making the Bernoulli distribution a discrete probability distribution. The probability of success is p, whereas the probability of failure is 1-p . A Bernoulli distribution has a mean of $E[X]=p$ and a variance Var[X]=p.(1-p).

We are aware that the mean of the Bernoulli distribution b(n,p) is given by np and variance =npq, where p is the probability of success and q=(1-p) is the probability of failure. Therefore   Variance $=q \times($ mean $)$

Therefore, the mean is greater than variance (p>pq) in Bernoulli distribution .

To know more about "Bernoulli distribution"

brainly.in/question/18560148

To know more about "mean and variance"

brainly.in/question/4117656

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