Question

write the relationship between the zeros and coefficients of the quadratic polynomial ax^2 + bx + c​

Answer 1

If

$\alpha \: and \ \: beta \: are \: the \: roots \: of \: the \: quadratic \: equation \: ax ^{2} + bx + c = 0 \\ then \: \alpha + \beta = \binom{ - b}{a} \: \: \: \: \ and \: \: \: \: \: \alpha \beta = c \div a$

Answer 2

We get the relation : $\alpha +\beta =\dfrac{-b}{a}\ and\ \alpha \beta =\dfrac{c}{a}$

Step-by-step explanation:

Since we have given that

Quadratic polynomial is

$ax^2+bx+c$

So, relationship between the zeroes and coefficients of the quadratic equation is given by

$\alpha +\beta =\dfrac{-b}{a}\\\\\alpha \beta =\dfrac{c}{a}$

Hence, we get the relation : $\alpha +\beta =\dfrac{-b}{a}\ and\ \alpha \beta =\dfrac{c}{a}$

# learn more:

Find a quadratic polynomial whose zeroes are reciprocal of the zeroes of the polynomial ax^2+bx+c

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