write the remainder obtain when 1!+2!+3!+...+200! is divisible by 14 with explanation
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14 is 2*7..
SO all terms from 7! till 200! will be div by 14..
We are left with 1!+2!+...+6!= 1+2+6+24+120+720= 873..
873= 14*62+5...
Remainder 5
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SO all terms from 7! till 200! will be div by 14..
We are left with 1!+2!+...+6!= 1+2+6+24+120+720= 873..
873= 14*62+5...
Remainder 5
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I request u
Please do it Please
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