write the remainder when 9xcube-3xsquare+x-5 divided by -2/3
Answers
Answered by
0
P(x)=-2/3
P(-2/3)=9(-2/3)cube - 3(-2/3) square+(-2/3)-5
=9(-8/27)-3(4/9)-2/3-5
=9*-8/27 -3*4/9-2/3-5
=-8/3 -4/3 - 2/3 - 5/1
=8-4-2-15/3
=-13/3 = remainder
P(-2/3)=9(-2/3)cube - 3(-2/3) square+(-2/3)-5
=9(-8/27)-3(4/9)-2/3-5
=9*-8/27 -3*4/9-2/3-5
=-8/3 -4/3 - 2/3 - 5/1
=8-4-2-15/3
=-13/3 = remainder
Similar questions