Question

write the respective chemical equations to show that what happens when 1.methane is burned in the presence of oxygen 2.ethanol is heated with conc.sulphuric acid at 443k? 3. ethanol reacts with ethanoic acid in the presence of an acid acting as a catalyst​

Answer 1

Explanation:

Methane is CH4 when it is burnt in oxygen it gives off heat and usually makes carbon dioxide and water

The balanced equation is: CH4 + 2 O2 ---> CO2 + 2 H20

If there is not enough oxygen sometimes it can also produce carbon monoxide (CO) instead of carbon dioxide.

Answer 2

Answer:

1- On Combustion (Reaction with O2) of methane

CH4 + 2O2. = CO2 +2H2O

CO2 evolved and H20 Formation

2- When ethanol reacts with con. Sulphuric acid Dehydration takes place (E2) (alpha -beta elimination) at 443Kelvin

CH3- CH2 -OH - CH2=CH2

Note = if Reaction takes place at 413 Kelvin

than Product is Ethoxy Ethane (Ether)

3--

Acid + Base = esterification Reaction

CH3OH + CH3COOH - CH3COOCH3

ester formation

methyl ethanoate