Question

write the roots of the following quadratic equation 1: (x-3) (x-2) =0​

Answer 1

Answer:

x−

x

1

=3

⇒x

2

−3x−1=0

⇒x=

2a

−b±

b

2

−4ac

⇒a=1,b=−3,c=−1

⇒x=

2

3±

9+4

⇒x=

2

3±

13

ii)

(x+4)

1

−

(x−7)

1

=

30

11

⇒

(x+4)(x−7)

(x−7−x−4)

=

30

11

⇒

(x+4)(x−7)

−11

=

30

11

⇒−30=x

2

−3x−28

⇒x

2

−3x+2=0

⇒x

2

−2x−x+2=0

⇒x(x−2)−1(x−2)=0

⇒(x−2)(x−1)=0

⇒x=1,2

Answer 2

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