write the rule for filling the electrons in various energy shells of any atom, as pfoposed by bohr and bury
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electrons in an energy shells could be filled by the formula 2n^2 where n is the shell no
suppose we have to find the no of electrons in 2nd shell so n will be 2 *4=8
suppose we have to find the no of electrons in 2nd shell so n will be 2 *4=8
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According to Bohr Bury Rule;
Every shell like K, L, M.... Etc have electrons whose number is equal to 2n^2 where n is shell number.. Or also called as Principal Quantum number.
For K : 2* 1^2 = 2*1 = 2e-
L : 2* 2^2 = 2* 4 = 8e-
M : 2* 3^2 = 2*9 = 18e-........
Energy of shell is increases with increasing order.. Means K have less energy than L.. And same like it follows :
K<L<M<N..
Next shell is start to fill after previous ones are completely filled.
Electrons in last shell is not more than 8..
For ex..
Ca have 20e-..
So it's electronic configuration need to be 2,8,10.
But according to fourth rule, third shell is last shell.. So it's contains only 8e-..
So it's electronic configuration is 2,8,8,2.
Hope it's helpful to u.
Every shell like K, L, M.... Etc have electrons whose number is equal to 2n^2 where n is shell number.. Or also called as Principal Quantum number.
For K : 2* 1^2 = 2*1 = 2e-
L : 2* 2^2 = 2* 4 = 8e-
M : 2* 3^2 = 2*9 = 18e-........
Energy of shell is increases with increasing order.. Means K have less energy than L.. And same like it follows :
K<L<M<N..
Next shell is start to fill after previous ones are completely filled.
Electrons in last shell is not more than 8..
For ex..
Ca have 20e-..
So it's electronic configuration need to be 2,8,10.
But according to fourth rule, third shell is last shell.. So it's contains only 8e-..
So it's electronic configuration is 2,8,8,2.
Hope it's helpful to u.
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