Question

Write the rules proposed for electron distribution under the Bohr-Bury scheme. Use the rules to
write the electronic configuration of given atoms. Also give the number of neutrons present in each
om. F. Mg, Si, P, 35C1​

Answer 1

Answer:

The distribution of electrons in different orbits or shells is governed by a scheme known as Bohr bury scheme.The arrangement of electrons in various energy levels of an atom is known as the electronic configuration of the atom. According to this scheme.

The electrons are arranged around the nucleus in different energy levels or energy shells. The electrons first occupy the shell with the lowest energy i.e., closest to the nucleus.

The first or the innermost energy shell (K or n = 1) can take only two electrons.

The second shell (L or n = 2) can contain upto 8 electrons.

From third shell (M or n = 3) onwards, the shells become bigger. The third shell can accommodate as many as 18 electrons. In general, the maximum number of electrons that can be present in any shell is 2n2 where n is the number of energy's shell. Thus, the first orbit (n = 1, known as K shell) can contain 2 × 12 = 2 electrons, the second orbit (n = 2, known as L shell) can contain 2 × 22 = 8 electrons.

Maximum No. of electrons in different orbits

Orbit

Value of nMaximum no. of electrons in the orbit

K

12 × 12 = 2L2

2 × 22 = 8

M

32 × 32 = 18N4

2 × 42 = 32

The outermost shell of an atom cannot have more than 8 electrons and the shell next to the outermost shell cannot have more than 18 electrons.