Physics, asked by Anonymous, 11 months ago

write the Schrodinger time independent equation ?
with mathmetical prove? ​

Answers

Answered by Anonymous
7

To support uncertainty principle E. Schrodinger utilized de Brogue's concept of matter wave and incorporated the wavelength expression into general classical wave equation.By this hi develop a wave equation for a moving particle which is known as Schrodinger's wave equation.At different point in space around nucleus.

on considering the oscillation along the axis x-axis the equation of standing wave is

 \psi = a \sin( \frac{2\pi \: x }{ \  \lambda })

Now

differentiating with respect to X we get

 \frac{ d\psi}{dx}  =  \frac{2\pi}{ \lambda} a \cos( \frac{2\pi \: x}{ \lambda} )

Again taking the second derivative

 \frac{ {d  }^{2} \psi }{d {x}^{2} }  =  \frac{2\pi}{ \lambda} a \sin( \frac{2\pi \: x}{ \lambda}   \times \frac{2\pi}{ \lambda} )  \\ \frac{ {d  }^{2} \psi }{d {x}^{2} }  =  \frac{4 {\pi}^{2} }{ \lambda} \psi \\

Extending the relation to three dimension we get

 \frac{ {d  }^{2} \psi }{d {x}^{2} }  + \frac{ {d  }^{2} \psi }{d {y}^{2} }  + \frac{ {d  }^{2} \psi }{d { z }^{2} }  =   - \frac{4 {\pi}^{2} }{  { \lambda}^{2} }

on putting lambda = h/mv we get

 { \delta}^{2}  \psi \:  +  \frac{8 {\pi}^{2}m}{ h}(E  - V ) \psi = 0

:-)

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