Write the sequence formed by the integer terms of the arithmetic sequence 19/8,11/4,25/8,.....?
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Answer:
5,6,7......
Step-by-step explanation:
a=19/8
d=11/4-19/8=3/8
19,22,25,28,31,34,37,40.......
a8=40
a16=19+15*3=19+45=64
first integer term of the sequence:40/8=5
2nd term:64/8=6
sequence: 5,6,7.....
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