Question

write the sequence of natural number which leaves remainder 3 in division by 5and 10​

Answer 1

Answer:

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Answer 2

Leaving Remainder as 3 When Divided by 5

We can the numbers through the method :

( 5 x 1 ) + 3 , ( 5 x 2) + 3 ..

As You Go , you can see that the difference between each number is 5

So The Sequence will be :

8 , 13 , 18 , 23 , 28, 33 , 38 , 43 , 48 , 53 , 58...

There is also Another pattern : Unit Digit is repeating with 8 and 3

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Leaving Remainder as 3 When Divided by 10

We can the numbers through the method :

( 10 x 1 ) + 3 , ( 10 x 2) + 3 ..

As You Go , you can see that the difference between each number is 10

So The Sequence will be :

13 , 23 , 33 , 43 , 53 , 63 , 73 ...

There is also Another pattern : Unit Digit is always 3

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Thank You ,

Hope It Helps ,

Abishek