Question

Write the sequence of natural numbers which leave a reminder 2 on division by 5​

Answer 1

Answer:

Step-by-step explanation:

If the division by 3 leads to remainder 1 then the sequence must be in the form of 3k+1.

So, the sequence is 1, 4, 7, 10

If the division by 3 leads to remainder 2 then the sequence must be in the form of 3k+2.

So, the sequence is 2, 5, 8, 11

Answer 2

Answer:

7,12,17,22,27,32,37

Step-by-step explanation:

7,12,17,22,27,32,37,42,47,52,57,62,67,72,77,82,87,92,97.. and so on.

The formula can be (5n +2 ) , 'n' belongs to natural number

Hope this helps