Question

write the sequence of squares of all odd numbers. what is its algebraic form?​

Answer 1

• xn = 2xn-1 =2n-1 So algebraic form of odd sequences = 2n-1 ii) Sequence of natural numbers which leave remainder 1 when division by 3 are 1, 4, 7, 10, and position 1,2,3,4, iii) Sequence of natural numbers ending in 1 are 1, 11, 21, 31

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Answer 2

Answer: Since

1^3=1

Sum of first 1odd no.

3^3=9

Sum of first 3 odd no.

then

x^3=sum of first x odd no.s

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