Question

write the set builder form of A={1,¼,¹/9,¹/16,¹/25} ​

Answer 1

Answer:

The set builder form of A is A=\{\frac{1}{x^2}:x\leq 5,x\in N\}A={

x

2

1

:x≤5,x∈N} .

Step-by-step explanation:

The given set is

A=\{1,\frac{1}{4},\frac{1}{9},\frac{1}{16},\frac{1}{25}\}A={1,

4

1

,

9

1

,

16

1

,

25

1

}

1=\frac{1}{1^2}1=

1

2

1

\frac{1}{4}=\frac{1}{2^2}

4

1

=

2

2

1

\frac{1}{9}=\frac{1}{3^2}

9

1

=

3

2

1

\frac{1}{16}=\frac{1}{4^2}

16

1

=

4

2

1

\frac{1}{25}=\frac{1}{5^2}

25

1

=

5

2

1

Therefore the number is in the form of \frac{1}{x^2}

x

2

1

, where x is a natural number less than equal to 5.

A=\{\frac{1}{x^2}:x\leq 5,x\in N\}A={

x

2

1

:x≤5,x∈N}

Therefore set builder form of A is A=\{\frac{1}{x^2}:x\leq 5,x\in N\}A={

x

2

1

:x≤5,x∈N} .

Answer 2

Answer:

variables representing an arbitrary member of set. ... The set A = {0, 1, 4, 9, . ... (i) {x О N : x2 < 25}. (ii) {x О R ... (a) {x : x О N : 9 < x < 16} (b) {x2 : x О N; 1 £ x £ 10} (c) 1. 2. 2 ... Solution : (i) Yes (ii) No, A ¹ B, as 12 О A and 12 П B (iii) Yes ... (iv) [– 23, 5) ={x : x О R, – 23 £ x < 5}. 8.

Step-by-step explanation:

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