Question

write the set of A all natural numbers `x' such that 4x+9<50 in roaster form
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Answer 1

Answer:

value of x can be 1,2,3,4,5

Answer 2

$\underline {\pink{ Set \: builder \: form \:of \:Set \: A }}$

$A = \{ x : 4x + 9 \lt 50 , \: x \in N \}$

$i) If \: x = 1 \: then \\4\times 1 + 9 = 4 + 9 \\= 13 \lt 50 \: \blue { ( True ) }$

$ii) If \: x = 2 \: then \\4\times 2 + 9 = 8 + 9 \\= 17 \lt 50 \: \blue { ( True ) }$

$iii) If \: x = 3 \: then \\4\times 3+ 9 = 12 + 9 \\= 17 \lt 50 \: \blue { ( True ) }$

$iv) If \: x = 4 \: then \\4\times 4 + 9 = 16 + 9 \\= 25 \lt 50 \: \blue { ( True ) }$

$v) If \: x = 5 \: then \\4\times 5 + 9 = 20 + 9 \\= 29 \lt 50 \: \blue { ( True ) }$

$vi) If \: x = 6\: then \\4\times 6 + 9 = 24 + 9 \\= 33 \lt 50 \: \blue { ( True ) }$

$vii) If \: x = 7 \: then \\4\times 7 + 9 = 28 + 9 \\= 38 \lt 50 \: \blue { ( True ) }$

$viii) If \: x = 8 \: then \\4\times 8+ 9 = 32+ 9 \\= 37 \lt 50 \: \blue { ( True ) }$

$ix) If \: x = 9 \: then \\4\times 9 + 9 = 36 + 9 \\= 45 \lt 50 \: \blue { ( True ) }$

$x) If \: x = 10 \: then \\4\times 10 + 9 = 40 + 9 \\= 49 \lt 50 \: \blue { ( True ) }$

$xi) If \: x = 11 \: then \\4\times 11 + 9 = 44 + 9 \\= 53 \lt 50 \: \red { ( False ) }$

$\underline {\pink{ Roster \: builder \: form \:of \:Set \: A }}$

$\red{A } \green { = \{ 1,2,3,4,5,6,7,8,9,10\}}$

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