Math, asked by sanasanaah532, 6 months ago

write the set of all natural numbers X such that 4x+9<50 in roaster form​

Answers

Answered by VedicLord
2

Answer:

X = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Step-by-step explanation:

4x + 9 &lt; 50 \\  or, 4x &lt; 41 \\  or,  x&lt; 10.25

Answered by Manmohan04
0

Given,

X is set of all natural numbers such that \[4x + 9 &lt; 50\]

Solution,

Put the values of x start from x = 1 up to x = 10.

It will satisfy the given algebraic condition.

But,

\[\begin{array}{l}at\,x = 11,\\4x + 9 &lt; 50\\ \Rightarrow 4 \times 11 + 9 &lt; 50\\ \Rightarrow 53 &gt; 50\end{array}\]

It is not satisfying algebraic expression at x = 11.

Hence x values from 1 to 10 satisfy the given condition.

Set of natural numbers in roaster form,

\[N = \left\{ {1,2,3,4,5,6,7,8,9,10} \right\}\]

Hence the set of natural numbers in roaster form is \[N = \left\{ {1,2,3,4,5,6,7,8,9,10} \right\}\]

Similar questions