Math, asked by meghakatiyar1, 1 year ago

write the set of all positive integers whose cube is odd.

don't span..

explain each and every step..​


Anonymous: by using roster or set builder form or both? xD

Answers

Answered by Anonymous
17

\mathfrak{\huge{\</em><em>blue</em><em>{Answer}}}

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Every odd number has an odd cube

Odd numbers can be represented as 2n+1.

{2n+1:n ϵ W} or

{1,3,5,7,……}

Here, n belongs to Z because the question says that it is a positive integer and the cube.

&lt;marquee direction="down"&gt;THANKS♥️✨


meghakatiyar1: n - not
Anonymous: means?
meghakatiyar1: check ur answer u have written
Anonymous: n is a whole no here.
Anonymous: ohh...I m sry
Anonymous: actually it will be {x:x = 2n+1, where n is an element of W}
Anonymous: ohh
Anonymous: now it is correct?
meghakatiyar1: but answer me hai n belongs to Z
1keshav123: hmm now it's correct ✔️
Answered by Anonymous
4

Answer:

Step-by-step explanation:

Heya user ✔✔✔

Here is ur ans⏏⏏

Even no are those no which have the 2 digit gap in there sum like,1 ,2 ,4 etc.

Same

Odd no are those no which are written as (2n+1 ) in sets form

Now roster form is

(x:x <=2n+1, where E belongs to W and N )

Both

✔✔Here we not take Z means Intergers because intergers are the no which is taken in both no as well as positive and negative too both

✔✔But the que is of positive no so we take all the positive no.

Hope it helps you

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