Question

Write the set of values of a for which the equation x^2+ax-2=0 has real roots

Answer 1

Answer:

- 2 = -2 * 1

    = 2 * -1

    = $\sqrt{2}$ * ( - $\sqrt{2}$)

a = -2 + 1   = -1

  = 2 + (- 1 )    =  1

  = $\sqrt{2}$ + (- $\sqrt{2}$) = 0