Question

Write the set of values of k for which the quadratic equation 2x^2+kx+8=0 has real roots n

Answer 1

Answer:

K = 2

Step-by-step explanation:

Given ; a = 2

b = 2k

c = 8

Also given that the equation has real roots,

Therefore, D = 0

D = b^2-4ac

0 = (2k)^2 - 4 *2*8

0 = 4k^2 - 64

64 = 4k^2

4k = 8 ( under root of 64)

k = 2.