Math, asked by aneenaneenu03, 10 months ago

write the simple form of sin^-1 [2x/1+x^2]

Answers

Answered by Anonymous

4

Step-by-step explanation:

Sin^-1 { 2x/1+x² }

let : x = tanO

O = tan-1(x)

Sin^-1 { 2tanO / 1 + tan²O }

Sin^-1 { Sin2O }

2O

= 2 tan^-1(x)

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