Question

write the simple form of sin^-1 [2x/1-x^2] please help
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Answer 1

Step-by-step explanation:

Sin^-1 { 2x/1+x² }

let : x = tanO

O = tan-1(x)

Sin^-1 { 2tanO / 1 + tan²O }

Sin^-1 { Sin2O }

2O

= 2 tan^-1(x)

Answer 2

Answer:

Letx = sin0 then 0 = sin-1 x

Then sin-1(2sin0 1 - sin20)

= sin-1 (2sin0cos0)

=sin-1 (sin20)

= 20

= 2sin-1x