Question

Write the simplest form of tan inverse 3 cosx-4 sinx/

Answer 1

Step-by-step explanation:

$let \: 3 \cos( \alpha ) - 4 \sin( \alpha ) = 0 \\ 3 \cos( \alpha ) = 4 \sin( \alpha ) \\ \frac{ \cos( \alpha ) }{ \sin( \alpha ) } = \frac{4}{3} \\ \cot( \alpha ) = \frac{4}{3} \\ \frac{1}{ \tan( \alpha ) } = \frac{4}{3} \\ \tan( \alpha ) = > \frac{3}{4}$

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