Question

Write the smallest 4 digit number using the digits 6,0 and 5 repeating 5 twice.

Answer 1

Given.

• The digits 6, 0 and 5

To find.

• The smallest 4 digit number using 5 twice

Solution.

• We have the four digits 6, 0, 5 and 5.

• Remember one idea: when there is a 0, we should find which digit is second to 0 i..e. just bigger than zero. We write that digit in the beginning and then the 0. After zero we write other digiits from smallest to largest.

• Here 5 is just bigger than 0. So we write 5 in the beginning and then 0. Remaining digits are 5 and 6, which can arranged as 56 since 5 < 6.

• Thus the required number is 5056.

Answer.

Smallest number is 5056.

Answer 2

Answer:

What is the smallest 4-digit number using each of the digits 3, 7, 0, and 9 once only?

Answer

7

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17 Answers



Ramkhilari Kushwah, B.Tech Mathematics & Vipassanā, Malaviya National Institute of Technology, Jaipur (1990)

Answered August 13, 2019

The given digit are: 0,3,7 and 9

For smallest number we have to take the digits as following:

The smallest digit at thousand place

0 is the smallest digit ,but if we take 0 at this place then number remains 3 digits

as 0379 =379

So we take next number bigger than 0 which is 3

2. Hundreds place smallest of remaining digits : 0,7,9 (i.e. 0)

3. Tens smallest of remaining digits : 7,9 (i.e. 7)

4. Ones place smallest of remaining digits : 9

So the smallest 4 digit Number becomes

= 3079