Write the smallest digit and the greater digit in the blank space of each of the following number so that the number formed is divisible by 3 A. _ 6724 B. 4765_2
Answers
Answer: A. 8 B. 9
Step-by-step explanation: (a) _6724
Sum of the remaining digits = 19
To make the number divisible by 3, the sum of its digits should be divisible by 3. The smallest multiple of 3 which comes after 19 is 21.
Therefore,
smallest number = 21 - 19 - 2
Now, 2 + 3 + 3 = 8 If we put 8, then the sum of the digits will be 27 and as 27 is divisible by 3, the number will also be divisible by 3.
Therefore, the largest number is 8.
(b) 4765_2
Sum of the remaining digits = 24
To make the number divisible by 3, the sum of its digits should be divisible by 3. As 24 is already divisible by 3, the smallest number that can be placed here is 0.
Now, 0 + 3 = 3 3 + 3 = 6 3 + 3 + 3 = 9
How ever, 3 + 3 + 3 + 3 = 12
If we put 9, then the sum of the digits will be 33 and as 33 is divisible by 3, the number will also be divisible by 3.
Therefore, the largest number is 9.
Answer:
A.8,B.6
Step-by-step explanation:
divisibility rule of 3 is that sum of no. should be a multiple of 3
therefore in 1st sum 6+7+2+4=19
highest no. will be 8 therefore 8+6+7+2+4=27
therefore in 2nd sum 4+7+6+5+2=24
highest no. will be 6
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