Question

Write the smallest digit and the greatest digit in the blank space of each of the following numbers so that the number formed is divisible by 3 : (a) __ 6724 (b) 4765 __ 2

Answer 1

(a) ___6724

6+7+2+4= 19

if we add 2 then the digit is divisible by 3 ( 19+2=21)

2 is the smallest digit

26724 = 2 + 6 + 7 + 2 + 4 = 21

if we add 8 then the digit is divisible by 3 ( 19+8=27)

8 is the largest digit

26724 = 8+ 6 + 7 + 2 + 4 = 36

b) (b) 4765 ___2

4+7+6+5+2=24

if we add 0 then the digit is divisible by 3 ( 24+0=24)

0 is the smallest digit

4765 ___2 = 4+ 7+6+5+0+2= 24

if we add 9 then the digit is divisible by 3 ( 24+9=33)

9 is the largest digit

4765 ___2 =4+ 7+6+5+9+2= 33

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Hope this will help you

Answer 2

Answer:

if sum of digits is multiple of 3

then the number is divisible by 3.

sum of digits is 24 .

the smallest possible digit is 0 which can make the sum of digits 24 which is divisible by 3.

the greatest possible digit is 9 which can make the sum of digits 33 which is divisible by 3.

final final answer zero

greatest digit is 9 .