Question

write the smallest digit and the greatest possible digit in the blank space of each of the following numbers so that the numbers formed are divisible by 3-6724 2nd 1476 5-2 3rd 722 1-5​

Answer 1

Answer:

A number is divisible by 3 if its sum of all digits is divisible by 3

(a) ___6724    

6+7+2+4= 19  

if we add 2 then the digit is divisible by 3  ( 19+2=21)

2 is the smallest digit  

26724 = 2 + 6 + 7 + 2 + 4 = 21

if we add 8 then the digit is divisible by 3  ( 19+8=27)

8 is the largest digit  

26724 = 8+ 6 + 7 + 2 + 4 = 36

b)  (b) 4765 ___2

4+7+6+5+2=24

if we add 0 then the digit is divisible by 3  ( 24+0=24)

0 is the smallest digit  

4765 ___2 = 4+ 7+6+5+0+2= 24

if we add 9 then the digit is divisible by 3  ( 24+9=33)

9 is the largest digit  

4765 ___2 =4+ 7+6+5+9+2= 33

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Hope this will help you

Answer 2

Answer:

this is ur answer

Step-by-step explanation:

it is correct