Question

write the smallest no. which is divisible by both 306 and 657 give answer in brief

Answer 1

Answer:

9

Step-by-step explanation:  

By Euclid's Division Algorithm

657 = 306*2 + 45

306 = 45*6 + 36

45 = 36*1 + 9

36 = 9*4 + 0

So, HCF 9

Answer 2

Smallest number is divisible by both 306 and 657 is 22338

Solution:

Given that,

We have to find the smallest number is divisible by both 306 and 657

Step 1:

Find the LCM of 306 and 657

List all prime factors for each number

Prime Factorization of 306 is:     2 x 3 x 3 x 17

Prime Factorization of 657 is:   3 x 3 x 73

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

2, 3, 3, 17, 73

Multiply these factors together to find the LCM

LCM = 2 x 3 x 3 x 17 x 73 = 22338

Thus the smallest number is divisible by both 306 and 657 is 22338

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