Write the smallest number by which 1188should be devided to make it a perfact cube
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hey here is your answer ✍✍✍✍✍......
First...
resolve 1188 into prime factors.
1188 = 2×2×3×3×3×11 ...
on grouping ,the factors ,we find 2×2×11 is left out ........so divide 1188 by 2×2×11 = 44....
The quotient then would be 3×3×3, which is a perfect cube .
☺☺☺therefore , 1188 must be divided by 44 so ,that the quotient become a perfect cube.....
hope it will help you..
Plz! mark it as braniliest
First...
resolve 1188 into prime factors.
1188 = 2×2×3×3×3×11 ...
on grouping ,the factors ,we find 2×2×11 is left out ........so divide 1188 by 2×2×11 = 44....
The quotient then would be 3×3×3, which is a perfect cube .
☺☺☺therefore , 1188 must be divided by 44 so ,that the quotient become a perfect cube.....
hope it will help you..
Plz! mark it as braniliest
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