Question

write the smallest number of 3 digits and divide it by the largest number of one digits

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Answer 1

Answer:

Prime factorisation of 22=2×11

Prime factorisation of 33=3×11

Prime factorisation of 55=5×11

So, LCM 22,33,55=2×3×5×11=330

As 330 is the smallest 3− digit number divisible by 22,33,55, the number 330+5=335 will give a remainder 5 when divided by these numbers.

The highest 3− digit number is 999.

999 when divived by 330 gives a remainder 9, so 999−9=990 is the largest 3− digit number divisible by 22,33,55, the number 990+5=995 will give a remainder 5 when divided by these numbers.

Answer 2

Step-by-step explanation:

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The smallest number of three digit is 100

The largest number of one digit is 9

100/9=11.111112