Math, asked by beditz2o, 11 months ago

write the smallest number which is divisible by both 306 and 657

Answers

Answered by samaira09

0

Answer:

22338

Step-by-step explanation:

Here, HCF= 9

We know that LCM= first no.* second no./ HCF

= 306*657/9

= 306*73

= 22338

Hence,the required no.is 22338

hope it helps you....

plzzz mark as brainlist.

Answered by arunagirivp1967

1

Answer:

nanum tamil thannn....

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