Math, asked by vishant01, 10 months ago

write the smallest number which is divisible by both 306 and 657​

Answers

Answered by lishanarang26
1

Answer:

We have to find smallest number which is divisible by 306 and 657

306 = 2 × 3² × 17

657 = 3 × 3 × 73

LCM of 306 and 657 = 2 × 3² × 17 × 73

= 2 × 9 × 17 × 73

= 18 × 17 × 73

= 306 × 73

= 22338

Hence, smallest number is 22338 which is divisible by 306 and 657.

Step-by-step explanation:

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