Question

Write the smallest numver which id dividiblr by both 306 and 657

Answer 1

Answer:

Step-by-step explanation:

Solution :-

H.C.F Of 306 , 657 is

by using prime factorisation method , we get ;

→ 306 = 2 × 3 × 3 × 17

→ 657 = 3 × 3 × 73

Therefore , H.C.F = 3 × 3 = 9 .

We know , Product of two numbers = H.C.F × L.C.M

H.C.F = 9, L.C.M = X

Now, 9 × X = 306 × 657

X = 306 × 657 / 9

So, L.C.M = 22338 Ans..

hopes it helps