Question

Write the smallest value of k so that 57k50 is divisible by 6​

Answer 1

Answer:

k=1

Step-by-step explanation:

divisibility rule of 6= the number must be divisible by 2 and 3.

Divisibility rule of 2 - It should be an even number.

Divisibility rule of 3- Sum of all digits must be a multiple of 3.

As this number 57k50 is already divisible by 2(even),

we will check it for 3

5+7+5+0= 17[not divisible by 3]

so k's smallest possible value would be 1

as if we add 1 to 17, then it would be divisible by 3.

Now, because 57150 is divisible by both 2 and 3, then it is also divisible by 6