write the solution set of the equation x^2+x-20=0 in roster form
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Answer:
x = 2
Step-by-step explanation:
given it x^2 + x-20 =0
so , x^2 + (5-4)x -20 = 0
x^2 + 5x - 4x -20 =0
2x ( x +5) - 4 ( x + 5 )=0
(2x-4) ( x + 5 ) = 0
then , 2x-4 = 0
so , 2x = 4
x = 4/2
x = 2
then , x+5 = 0
so , x = - 5 (असंगत )
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