Question

Write the solution set of the equation x2 + x -- 6 = 0 in roster form
{2, -3}
{-1, -2
{1,2}
{-1, 2}​

Answer 1

Answer:

2,-3 is the answer....

Answer 2

The value of the zeroes here is 2 and -3. These can be written in roster form [2,-3].

Step-by-step explanation:

Given expression:

$x^{2}$+ x- 6

To find= the zeroes of the given expression

Solution:

$x^{2}$+ x- 6

Using the middle-term splitting method:

$x^{2}$+ (3x-2x)+6

($x^{2}$+ 3x)-(2x+6)

x(x+ 3)-2(x+3)

(x-2)(x+3)

x= 2 and x= -3

Result:

Thus the value of the zeroes here is 2 and -3. These can be written in roster form [2,-3].

(#SPJ3)