Question

write the squared of the following (a+1/2)



formula x^2+2xy+y^2​

Answer 1

Answer:

(x + y)² = x² + y² + 2xy

x² + y² = (x + y)² - 2xy ………..(1)

(b) (x - y)² = x² + y² - 2xy

x² + y² = (x - y)² + 2xy ………..(2)

(c) in a complex number i = √(−1) => i² = -1

then x² + y² = x² + (-1)(-1)y²

x² + y² = x² - i².y²

x² + y² = x² - (iy)²

x² + y² = (x + iy).(x - iy) …………(3) [ since a² - b² = (a + b).(a - b) ]

Equation (1),(2) and (3) are general generate formulas for x²+y².

Answer 2

Answer:

(a+1/2)^2

(a)^2+ 2×(a)(1/2)+ (1/2)^2

a^2+a+1/4 -----------ans