Question

write the standard equaation for the circle center (-6, -8), that passes through (0,0)

Answer 1

Since the Centre is at the origin, this is the point (0 , 0). Since another point on the circle is (-6,-8), that is the (x,y) value. So let's plug it into the equation:

(-6-0)^2 + (-8-0)^2 = r^2

or, (-6)^2 + (-8)^2 = r^2

or, 36 + 64 = r^2

or, 100 = r^2

or, 10 = r

ans

Then using formula;;

• (x - 6)^2 + (y - 8)^2 = 10
• (x + 6)^2 + (y + 8)^2 = 14
• (x - 6)^2 + (y - 8)^2 = 196
• (x + 6)^2 + (y + 8)^2 = 100

it's help u