Question

Write the standard equation of a circle with center (−9, −4) and radius $\sqrt{5}$.


(x + 9)2 + (y + 4)2 = 5


(x – 4)2 + (y – 9)2 = 5


(x + 4)2 + (y + 9)2 = 5


(x – 9)2 + (y – 4)2 = 5

Answer 1

Step-by-step explanation:

since equation of a circle of centre( h,k) and radius = r

=> (x-h)²+(y-k)²=r²

=> {x-(-9) }²+{y-(-4)}² = (√5)²

=> (x+9)²+(y+4)²= 5

this is the standard eqn .

option first is correct.