Math, asked by julietvarshano1, 2 days ago

Write the statement for the following expression.
A. 4x
B. 5+ 7
C. 6 - y
D. 8 ÷ a
E. 5y + 8
2. Write the expression for the given statement.
A. Taking away 5 from y
B . Five times a number p
C. Add 7 to three times x
D. One fifth of n is added to 11

Answers

Answered by modishgamer2005
0

(i) x + 3 = 0

L.H.S. = x + 3

By putting x = 3,

L.H.S. = 3 + 3 = 6 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ii) x + 3 = 0

L.H.S. = x + 3

By putting x = 0,

L.H.S. = 0 + 3 = 3 ≠ R.H.S.

∴ No, the equation is not satisfied.

(iii) x + 3 = 0

L.H.S. = x + 3

By putting x = −3,

L.H.S. = − 3 + 3 = 0 = R.H.S.

∴ Yes, the equation is satisfied.

(iv) x − 7 = 1

L.H.S. = x − 7

By putting x = 7,

L.H.S. = 7 − 7 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(v) x − 7 = 1

L.H.S. = x − 7

By putting x = 8,

L.H.S. = 8 − 7 = 1 = R.H.S.

∴ Yes, the equation is satisfied.

(vi) 5x = 25

L.H.S. = 5x

By putting x = 0,

L.H.S. = 5 × 0 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(vii) 5x = 25

L.H.S. = 5x

By putting x = 5,

L.H.S. = 5 × 5 = 25 = R.H.S.

∴ Yes, the equation is satisfied.

(viii) 5x = 25

L.H.S. = 5x

By putting x = −5,

L.H.S. = 5 × (−5) = −25 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ix) = 2

L.H.S. =  

By putting m = −6,

L. H. S. =  ≠ R.H.S.

∴No, the equation is not satisfied.

(x) = 2

L.H.S. =  

By putting m = 0,

L.H.S. =  ≠ R.H.S.

∴No, the equation is not satisfied.

(xi) = 2

L.H.S. =  

By putting m = 6,

L.H.S. =  = R.H.S.

∴ Yes, the equation is satisfied.Answer:

Step-by-step explanation:

Answered by sisodiasaanvi0004
0

455454545544554545+2

Similar questions