Chemistry, asked by rathorearvind156, 7 months ago

write the steps of ionization of sulfuric acid in aqueous solution

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Answers

Answered by vishaldhir52
1

Answer:

Sulfuric acid disassociates in two steps. In both cases, hydrogen ions (protons), H+, split off and bond with water molecules forming hydronium ions, H3 O+1. The arrangement of hydrogen in hydronium is more stable than in the bond with the sulfate ion so energy is released as heat making this an exothermic reaction.

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rathorearvind156: @vishaldhir please don't copy other websites answer. I am not able to understand that's why I asked here
rathorearvind156: Please don't do this
vishaldhir52: it's not like that
vishaldhir52: i first read and added some imp points
rathorearvind156: Okay so tell what's the meaning of H3O+1
vishaldhir52: hydrated proton
rathorearvind156: Please answer the question again properly in simple language
Answered by vansh295045
0

Answer:

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