Question

Write the structural formulae of all possible isomers of the
compound with molecular formula C4H10O. Identify the
different isomer pairs from them and find the type of
isomerism to which each pair belongs.

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Answer 1

Answer:

Therefore there are a total of 7 isomers for the molecular formula C₄H₁₀O

Explanation:

• We know from the formula that these isomers contain no rings or double bonds.

• These isomers must be alcohols or ethers.

1. Start with four carbons in a row and put an OH group in every possible position...

• CH ₃CH ₂CH₂ CH ₂ OH  = butan-1-ol
• CH₃CH₂CH(OH)CH₃ = butan-2-ol

2. Use a 3-carbon chain with a CH₃ on the middle carbon...

• (CH₃)₂CHCH₂OH = 2-methyl-propan-1-ol
• (CH₃)₃COH = 2-methyl-propan-2-ol

3. For the ethers,we can write with 5 atoms in a row...

• CH₃CH₂CH₂OCH₃ = 1-methoxypropane
• CH₃CH₂OCH₂CH₃ = ethoxyethane

4. The only choice for a branched chain ether is

• (CH₃)₂CHOCH₃ = 2-methoxypropane

Therefore there are a total of 7 isomers for the molecular formula C₄H₁₀O

Answer 2

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★ Concept :

➙ In chemistry, isomers are molecules or polyatomic ions with identical molecular formulas — that is, same number of atoms of each element — but distinct arrangements of atoms in space.

➙ Isomerism is existence or possibility of isomers.

➙ Isomers do not necessarily share similar chemical or physical properties.

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Solution :

A) CH₃ - CH₂ - CH₂ - CH₂ - OH

B) CH₃ - CH - CH₂ - CH₃

〡

OH

C) Ch₃ - O - CH₂ - CH₂ - CH₃

D) CH₃ - CH₂ - O - CH₂ - CH₃

E) CH₃ - CH - CH₂ - OH

F) OH

〡

CH₃ - C - CH₃

〡

CH₃

➺ Therefore, there are 7 isomers of the molecular C₄H₁₀O.