Write the subshell electronic configuration of 24 Cr .
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Cr (Z = 24) = 1s2, 2s2 2p6 3s2 3p6 4s1 3d5. cr3+ = 1s2, 2s2 2p6 3s2 3p6 4s0 3d3. There are three unpaired electrons present in the 3d subshell.
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