Question

write the subshll electronic configuration of 24cr​

Answer 1

Answer:Cr (Z = 24) = 1s2, 2s2 2p6 3s2 3p6 4s1 3d5.

Step-by-step explanation: = 1s2, 2s2 2p6 3s2 3p6 4s0 3d3. There are three unpaired electrons present in the 3d subshell.

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Answer 2

Answer:

The subshell electronic configuration of $Cr_{24}$ is as follows:

$1s^{2}2s^{2}2p^{6}3s^{2} 3p^{6}4s^{1}3d^{5}$

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