write the sum and product of the zeros of the polynomial 2 - 8x²
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Find the sum and product of zeroes of polynomials 2x^2 - 8x + 6 .
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2 x^2 - 8 x + 6 = 0 2 x^2 - 2 x - 6 x + 6 = 0 2 x(x - 1) - 6(x - 1) = 0 x = 1 or 3 So 1,3 are the zeroes of polynomial 2 x^2 - 8 x + 6 Sum of zeroes is 1 + 3 = 4 Product of zeroes is 1(3) = 3
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