Question

Write the sum and product of zeroes of a quadratic polynomial are-4/5 , 7/25

Answer 1

hєчα

hєrє íѕ thє αnѕwєr

gívєn zєrσєѕ :-

-4 / 5 αnd 7 / 25.

tσ fínd :-

ѕum σf zєrσєѕ =?

prσduct σf zєrσєѕ =?

ѕσlutíσn :-

ѕum σf zєrσєѕ = (-4 / 5) + (7 / 25)

=> [(-4)(5) + 7] / 25

=> (-20 + 7) / 25

=> -13 / 25

prσduct σf zєrσєѕ = (-4 / 5) × (7 / 25)

=> (-4 × 7) / (5 × 25)

=> -28 / 125

thє quαdrαtíc єquαtíσn íѕ :-

p(х) = k [х² - (ѕum σf zєrσєѕ)х + (prσduct σf zєrσєѕ)]

p(х) = k [х² - (-13 / 25)х + (-28 / 125)]

p(х) = k [х² + (13 / 25)х - 28 / 125]

tαkíng l.c.m.

p(х) = k [(125х² + 65х - 28) / 125]

p(х) = k / 125 [125х² + 65х - 28]

put k = 125

p(х) = 125х² + 65х - 28.

hσpє thíѕ hєlpѕ.