write the sum and products of the roots of the x^2 +9=0
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Answered by
1
Answer:
THus sum of roots=-(b/a)=-(0/1)=0
product of zeros=c/a=9/1=9
Step-by-step explanation:
x^2 +9=0
or x²-0*x+9=0
here a=1 b=0, c=9
THus sum of roots=-(b/a)=-(0/1)=0
product of zeros=c/a=9/1=9
Answered by
4
Therefore,
x= ±root(-4×1×9) / (2)
x= ±root(-36) / 2
x =±4i / 2 , where i=root(-1)
x= ±2i
x= 2i , - 2i
—these are roots of the equation.
@deba65 you can also solve it.. as solved by kuswaindia.... that's formula
But ans is totally different.. u see
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