Math, asked by deba65, 8 months ago

write the sum and products of the roots of the x^2 +9=0​

Answers

Answered by Anonymous
1

Answer:

THus sum of roots=-(b/a)=-(0/1)=0

product of zeros=c/a=9/1=9

Step-by-step explanation:

x^2 +9=0​

or x²-0*x+9=0

here a=1 b=0, c=9

THus sum of roots=-(b/a)=-(0/1)=0

product of zeros=c/a=9/1=9

Answered by MichSuchana91
4

Therefore,

x= ±root(-4×1×9) / (2)

x= ±root(-36) / 2

x =±4i / 2 , where i=root(-1)

x= ±2i

x= 2i , - 2i

—these are roots of the equation.

@deba65 you can also solve it.. as solved by kuswaindia.... that's formula

But ans is totally different.. u see

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