write the sum of exponents of prime factors in the prime factorisation of 25022.
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To find:
Sum of exponents of prime factors in the prime factorization =?
Solution:
Now, let us first take the prime factors of the number 25022, we get 2 x 12511
Now the prime factor grouped together can be written as 2 x 12511
Hence, the exponents for 2 and 12511 are 1 and 1 respectively; therefore the sum of the exponent is 1 + 1 = 2
Hence, the sum of exponents of prime factors in the prime factorization of 25022 = 2.
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