Question

write the sum of exponents of prime factors of 98.

Answer 1

98 = 2×7×7 = 2¹ × 7²
Sum of exponents = 1+2 = 3

Answer 2

Answer:

The sum of the exponents of 98’s prime factors is 3.

To find:

Exponent’s sum of the prime factors of the given number 98.

Solution:

Prime factors of 98 can be found out by factorising the number 98,

Accordingly we get the prime factors of 98,

$\therefore 98 = 2 \times 7 \times 7 \times 1 = 2 ^ { 1 } \times 7 ^ { 2 }$

According to the question,

The sum of the exponents of the given prime factors of 98 = 1 + 2 = 3.